In the following questions more than one correlation is possible between options of both columns. Free download Class 11 Chemistry Thermodynamics Questions and Answers.Ribblu launches platform for supplying free download of CBSE Sample board exam papers & worksheets from nursery to class … Give the significance of sign also. Register online for Chemistry tuition on Vedantu.com to score more marks in your examination. The above NCERT CBSE and KVS MCQs for Class 11 Chemistry will help you to boost your scores as multiple choice questions have been coming in your examinations. Specific heat of $L i(\mathrm{s}), N a(\mathrm{s}), K(s), R b(s)$ and $C s(s)$ at $398 K$ are $3.57,1.23,0.756,0.363$ and $0.242 \mathrm{Jg}^{-1} \mathrm{K}^{-1}$ respectively. Enthalpy is defined as heat content of the system $H=U+P V$, Enthalpy change is measured at constant pressure, The enthalpy change $(\Delta H)$ for the reaction, $N_{2}(g)+3 H_{2}(g) \rightarrow 2 N H_{3}(g)$ is $-92.38 k J$ at $298 K .$ What is, $\Delta U$ at $298 K ? Although heat is a path function but heat absorbed by the system under certain specific conditions is independent of path. Why would you expect a decrease in entropy as a gas condenses into liquid ? Download India's Best Exam Preparation App. On the basis of thermochemical equations (a), (b) and (c), find out which of the algebric relationships given in options (i) to (iv) is correct. Answer. Calculate Gibbs energy change for the reaction is spontaneous or not. Also, the order of entropy for the three phases of the matter is $S(g)>>S(l)>S(s)$. The surrounding of a system is the part of the universe that does not contain the system. This unit is part of the Chemistry library. Standard molar enthalpy of formation, Δ, Enthalpy is an extensive property. Calculate the work done and the change in internal energy when 1 litre of ideal gas expands isothermally into vacuum until its total volume is 5 litre? Candidates who are ambitious to qualify the Class 11 with good score can check this article for Notes. A sample of 1.0 mol of a monoatomic ideal gas is taken through a cyclic process of expansion and compression as shown in Fig. Important questions for Class 11 Chemistry are very crucial for the final examination as well as for those students who are preparing for the competitive examinations. Question of Exercise 1. q v = ΔU. Calculate $\Delta S$ for the conversion of: (ii) Vapours to liquid at $35^{\circ} \mathrm{C}$, $\Delta S_{v a p . CBSE Chemistry Chapter 6 Thermodynamics class 11 Notes Chemistry in PDF are available for free download in myCBSEguide mobile app. Learn and practice from Thermodynamics quiz, study notes and study tips to help you in NEET Chemistry preparation. (iii) $\quad \mathrm{CaCO}_{3}(s) \rightarrow \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{g})$, (iv) $\quad N_{2}(g)(1 \mathrm{atm}) \rightarrow N_{2}(g)(0.5 \mathrm{atm})$. Calculate the standard enthalpy of formation of $C H_{3} O H(l)$ from the following data: $\mathrm{CH}_{3} \mathrm{OH}(l)+\frac{3}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)$, $\Delta_{r} H^{\circ}=-726 k J m o l^{-1}$, $C(g)+O_{2}(g) \rightarrow C O_{2}(g) ; \Delta_{r} H^{\circ}=-393 k J m o l^{-1}$, $H_{2}(g)+\frac{1}{2} O_{2}(g) \rightarrow H_{2} O(l) ; \Delta_{r} H^{\circ}=-286.0 k J m o l^{-1}$, $C(\text { graphite })+2 H_{2}(g)+\frac{1}{2} O_{2}(g) \longrightarrow C H_{3} O H(l)$, (i) $\left.\quad \mathrm{CH}_{3} \mathrm{OH}(l)+\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)\right]$, (ii) $\quad C(g)+O_{2}(g) \longrightarrow C O_{2}(g) ; \Delta_{r} H^{\circ}=-393 k J m o r^{1}$, (iii) $H_{2}(g)+\frac{1}{2} O_{2}(g) \longrightarrow H_{2} O(\eta) ; \Delta_{r} H^{\circ}=-2860 \mathrm{kJ} \mathrm{mol}^{-1}$, Multiply eqn. Solve marks wise questions of all types. Our social links. ( } i v)$, (i) $\quad \mathrm{CH}_{3} \mathrm{OH}(l)+\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O}(l)$, $\Delta_{r} H^{\circ}=-726 \mathrm{kJmol}^{-1}$, $C_{(G r a p h i t e)}+2 H_{2}(g)+\frac{1}{2} O_{2}(g) \longrightarrow C H_{3} O H(l)$, $\Delta_{r} H^{\circ}=-239 k J m o l^{-1}$. (i) Write the relationship between $\Delta H$ and $\Delta U$ for the process at constant pressure and temperature. Calculate the enthalpy change when $10.32 g$ of phosphorus reacts with an excess of bromine. According to first law of thermodynamics, q= ΔU + PΔV. The state of a gas can be described by quoting the relationship between___. (ii) At what temperature, the reaction will reverse? Thermodynamics - Chemistry Notes, Questions and Answers, Free Study Material, Chapter wise Online Tests. It … Solved Problems on Thermodynamics:-Problem 1:-A container holds a mixture of three nonreacting gases: n 1 moles of the first gas with molar specific heat at constant volume C 1, and so on.Find the molar specific heat at constant volume of the mixture, in terms of the molar specific heats and quantitites of the three separate gases. -condensation into a liquid. Explain each term involved in the equation. C No sign . Important questions, guess papers, most expected questions and best questions from 11th Chemistry chapter 06 Thermodynamics have CBSE chapter wise important questions with solution for free download in PDF format. Browse videos, articles, and exercises by topic. Thermodynamics is an important, but easy to score chapter for NEET UG medical exams. Go Back to Chemistry Home Page Physics Maths Biology. But $\mathrm{NO}_{2}(g)$ is formed. Another thermodynamic quantities that helps in predicting the spontaneity of a process is Gibbs free energy or Gibbs energy of Gibbs function. Last Updated on March 20, 2019 By Mrs Shilpi Nagpal 1 Comment. 1; 2; 3 » Question No : 1 In a thermal decomposition reaction, sign of ∆ H may be... A positive . eSaral provides you complete edge to prepare for Board and Competitive Exams like JEE, NEET, BITSAT, etc. Predict the sign of entropy change for each of the following changes of state: (ii) $\quad A g N O_{3}(s) \rightarrow A g N O_{3}(a q)$, (iii) $\quad I_{2}(g) \rightarrow I_{2}(s)$. Class 11+12 – Chemistry; Class 11+12 – Biology; IIT/NEET Foundation. Thermodynamics of Class 11. This will be so if. What is meant by average bond enthalpy ? CBSE Class 11 Chapter 6 Thermodynamics Chemistry Marks Wise Question with Solutions. Explanation are given for understanding. Match the following processes with entropy change: Match the following parameters with description for spontaneity : Assertion (A): Combustion of all organic compounds is an exothermic reaction. In an exothermic reaction, heat is evolved, and system loses heat to the surrounding. $-228.6 \mathrm{kJmol}^{-1}$ respectively. JEE NEET Study Material : Notes , Assignment . Third law of thermodynamics provides a method to evaluate which property? Explain both terms with the help of examples. This question bank is designed by expert faculties keeping NCERT in mind and the questions are updated with respect to upcoming Board exams. CBSE Class 11 Chemistry Thermodynamics – Get here the Notes for Class 11 Thermodynamics. This question bank is designed by expert faculties keeping NCERT in mind and the questions are updated with respect to upcoming Board exams. (i) $\quad C H_{4}(g)+2 O_{2}(g) \rightarrow C O_{2}(g)+2 H_{2} O(g)$, $\Delta G_{f}^{o} \mathrm{CO}_{2}(g)=-394.36 \mathrm{kJ} \mathrm{mol}^{-1}$, $\Delta G_{f}^{\circ} H_{2} O(g)=-228.57 k J m o l^{-1}$, $\Delta G_{f}^{\circ} C H_{4}(g)=-50.72 \mathrm{kJ} \mathrm{mol}^{-1}$ and $\Delta \mathrm{G}_{f}^{\circ} \mathrm{O}_{2}(g)=0$, (ii) $\operatorname{CaCQ}(s)+2 H^{+}(a q) \rightarrow C a^{2+}(a q)+H_{2} O(l)+C O_{2}(g)$, $\Delta G_{f}^{\circ} C a^{2+}(a q)=-553.58 k J m o l^{-1}$, $\Delta G_{f}^{\circ} H_{2} O(l)=-237.13 k J m o l^{-1}$, $\Delta G_{f}^{\circ} C O_{2}(g)=-394.36 k J m o l^{-1}$, $\Delta G_{f}^{o} C a C O_{3}(g)=-1206.9 \mathrm{kJ} \mathrm{mol}^{-1}$, $-\left[\Delta G_{f}^{\circ} C H_{4}(g)+2 \Delta G_{f}^{\circ} O_{2}(g)\right]$, $=[-394.36+\{2 \times(-228.57)\}-[-50.72+0]$, (ii) $\Delta G_{r}^{\circ}=\left[\Delta G_{f}^{\circ} \mathrm{C} a^{2+}(a q)+\Delta G_{f}^{\circ} H_{2} O(l)+\Delta G_{f}^{\circ} \mathrm{CO}_{2}(g)\right]$, $\quad-\left[\Delta G_{f}^{\circ} \mathrm{CaCO}_{3}(\mathrm{s})+2 \Delta G_{f}^{\circ} \mathrm{H}^{+}(a q)\right]$, $=[-553.58+(-237.13)+(-394.36)]-[-1206.9+0]$, (ii) $\quad \Delta G_{r}^{\circ}=\left[\Delta G_{f}^{\circ} \mathrm{C} a^{2+}(a q)+\Delta G_{f}^{\circ} H_{2} \mathrm{O}(l)+\Delta G_{f}^{\circ} \mathrm{CO}_{2}(g)\right]$, $-\left[\Delta G_{f}^{\circ} \mathrm{CaCO}_{3}(s)+2 \Delta G_{f}^{\circ} H^{+}(a q)\right]$, Calculate the standard molar entropy change for the following reactions at $298 K$, (i) $\quad 4 F e(s)+3 O_{2}(g) \rightarrow 2 F e_{2} O_{3}(s)$, $S^{\circ}(F e(s))=27.28 \mathrm{JK}^{-1} \mathrm{mol}^{-1}$, $S^{\circ}\left(O_{2}(g)\right)=205.14 J K^{-1} m o l^{-1}$, $S^{\circ}\left(F e_{2} O_{3}(s)\right)=87.4 \quad J K^{-1} m o l^{-1}$, (ii) $\quad C a(s)+2 H_{2} O(l) \rightarrow C a(O H)_{2}(a q)+H_{2}(g)$, $S(C a(s))^{\circ}=41.42 \quad J K^{-1} m o l^{-1}$, $S^{\circ}\left[H_{2} O(l)\right]=69.91 J K^{-1} m o l^{-1}$, $S^{\circ} \mathrm{Ca}(\mathrm{OH})_{2}(a q)=-74.50 \mathrm{JK}^{-1} \mathrm{mol}^{-1}$, $S^{\circ}\left(H_{2}\right)(g)=130.68 J K^{-1} m o l^{-1}$, $=\left(2 S_{F e_{2} O_{3}}^{\circ}\right)-\left(4 S_{F e(s)}^{\circ}+3 S_{O_{2}}^{\circ}(g)\right)$, $=(2 \times 87.4)-(4 \times 27.28+3 \times 205.14)$, $=(174.8)-(724.54)=-549.74 \mathrm{JK}^{-1} \mathrm{mol}^{-1}$, (ii) $\quad \Delta S_{\text {reaction}}^{\circ}=\Sigma S^{\circ}(\text { products })-\Sigma S^{\circ}(\text { reactans })$, $=\left(S_{C a(O H)_{2}}^{\circ}(a q)+S_{H_{2}(g)}^{\circ}-\left(S_{C a(s))}^{\circ}+2 S_{H_{2} O(l)}^{\circ}\right)\right.$, $=\{-74.50+130.68\}-\{41.42+(2 \times 69.91)\}$, $\Rightarrow 56.18-(41.42+139.82) \Rightarrow-125.06 J K^{-1} \mathrm{mol}^{-1}$, $\Delta H=-10,000 J \mathrm{mol}^{-1}, \Delta S=-33.3 \mathrm{J} \mathrm{mol}^{-1} \mathrm{K}^{-1}$. The enthalpies of elements in their standard states are taken as zero. BETA version [email protected] ALPHA XI PHYSICS. Thermodynamics MCQ Question with Answer Thermodynamics MCQ with detailed explanation for interview, entrance and competitive exams. Compute the molar heat capacity of these elements and identify any periodic trend. Thus, entropy increases. When liquid benzene is oxidised at constant pressure at 300 K, the change in enthalpy is -3728 kJ. Surroundings: Everything else in the universe except system is called surroundings. the standard Gibbs energy for the reaction at $1000 K$ is $-8.1 \mathrm{kJmol}^{-1} .$ Calculate its equilibrium constant. (a) Absolute Energy (b) Absolute Enthalpy (c) Absolute Entropy (d) Absolute Free Energy. Silane $\left(S i H_{4}\right)$ burns in air as: $\operatorname{SiH}_{4}(g)+2 O_{2}(g) \rightarrow \operatorname{Si} O_{2}(s)+2 H_{2} O(l)$, The standard Gibbs energies of formation of $S i H_{4}(g), S i O_{2}(s)$ and $H_{2} O(l)$ are $+52.3,-805.0$ and. Question from very important topics are covered by NCERT Exemplar Class 11. Answer: (c) … The net enthalpy change of a reaction is the amount of energy required to break all the bonds in reactant molecules minus amount of energy required to form all the bonds in the product molecules. Treat heat capacity of water as the heat capacity of calorimeter and its content). All educational material on the website has been prepared by the best teachers having more than 20 years of teaching experience in various Enthalpy diagram for a particular reaction is given in Fig. $0=\Delta H-T \Delta S$ or $\Delta H=T \Delta S$ or $T=\frac{\Delta H}{\Delta S}$, Here, $\Delta H=30.56 \mathrm{kJ} \mathrm{mol}^{-1}=30560 \mathrm{J} \mathrm{mol}^{-1}$, $\Delta S=66.0 \mathrm{JK}^{-1} \mathrm{mol}^{-1}$, $\therefore \quad T=\frac{30560}{66.0}=463 \mathrm{K}$, (i) At $463 K,$ the reaction will be at equilibrium because $\Delta G$ is, (ii) Below this temperature, $\Delta G$ will be $+$ve because both $\Delta \mathrm{H}$ and $\mathrm{T} \Delta \mathrm{S}$ are positive and $\Delta \mathrm{H}>\mathrm{T} \Delta \mathrm{S}(\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}=+\mathrm{ve})$. A piston exerting a pressure of 1 atm rests on the surface of water at $100^{\circ} \mathrm{C} .$ The pressure is reduced to smaller extent when $10 g$ of water evaporates and $22.2 \mathrm{kJ}$ of heat is absorbed. Here, students can access detailed, explanative solutions to all the intext and exercise questions listed in chapter 6 of the NCERT Class 11 chemistry textbook. Pressure, volume and temperature depends on the state of the … In the following questions two or more options may be correct. or own an. 011-47340170 . Questions on Chemistry, Thermodynamics: MCQs test on 'Chemistry, Thermodynamics' with answers, Test: 1, Total Questions: 15 (i) The presence of reacting species in a covered beaker is an example of open system. As no heat is absorbed by the system, the wall is adiabatic. These important questions from thermodynamics class 11 physics will play significant role in clearing concepts of Physics. CBSE Class 11 Chapter 6 Thermodynamics Chemistry Marks Wise Question PDF. NCERT Solution of Thermodynamics Chemistry Class 11. The enthalpy of formation of a compound, Enthalpy of sublimation of a substance is equal to, (i) enthalpy of fusion + enthalpy of vapourisation, (ii) ΔG is positive for a spontaneous reaction, (iii) ΔG is negative for a spontaneous reaction, (iv) ΔG is positive for a non-spontaneous reaction. $T=\frac{\Delta H}{\Delta S}=\frac{-10000 J m o l^{-1}}{-33.3 J K^{-1} m o l^{-1}}=300.3 \mathrm{K}$, (i) For spontaneity from left to right, $\Delta G$ should be $-v e$ for the given reaction. This question bank is designed, keeping NCERT in mind and the questions are updated with respect to upcoming Board exams. During complete combustion of one mole of butane, 2658 kJ of heat is released. Explain whether the diffusion of these gases into each other in a closed container is a spontaneous process or not? (ii) ΔS (system) increases but ΔS (surroundings) decreases. Thermodynamics Physics First law Second Law Zero Law Cp Cv Work Heat Thermal Equilibrium Carnot's Heat Engine Isothermal Adiabatic. To help the students to prepare for examination more effectively, we provide CBSE marks wise questions for Class 11 are given here. What is the sign of $\Delta S$ for the forward direction? (iv) burning carbon in oxygen to give carbon dioxide. Also calculate enthalpy of solution of ammonium nitrate. Open System: In a system, when there is exchange of energy and matter taking place with […] Thermodynamics Questions with Solutions to help you to revise complete Syllabus and Score More marks in your Class 11 Examinations. $\Delta G=\Delta H-T \Delta S-v e=\Delta H-(+v e)(-v e)$. It is impossible to determine it directly by experiment. Do check out the sample questions of MCQ: Chapter 6 - Thermodynamics, Class 11, Chemistry JEE Notes | EduRev for JEE, the answers and examples explain the meaning of chapter in the best manner. 1.0 mol of a monoatomic ideal gas is expanded from state (1) to state (2) as shown in Fig. Question of Exercise 1. These important questions will play significant role in clearing concepts of Chemistry. }=\frac{\Delta H_{v a p . Choose the correct answer: Question 1. (Given that power $=$ energy/time and $\left.1 W=1 J s^{-1}\right)$, $\left(C_{6} H_{6}\right)=(6 \times 12)+(6 \times 1)=78$, $\therefore$ Energy required to vapourise $100 g$ benzene, $=\frac{30.8}{78} \times 100=39.487 k_{U}=39487 J$, Given that power $=\frac{\text { Energy }}{\text { time }} \Rightarrow$ time $=\frac{\text { energy }}{\text { power }}$, Time $=\frac{39487 \mathrm{J}}{100 \mathrm{Js}^{-1}}=394.87 \mathrm{s}$, Calculate the enthalpy change when $2.38 g$ of $C O$ vapourise at its boiling point. $H-O-H \rightarrow H(g)+O H(g) ; \Delta H=498 k_{\mathrm{d}}$, $O-H(g) \rightarrow O(g)+H(g) ; \Delta H=430 k J$, Average bond enthalpy $\Delta H(O-H)=\frac{498+430}{2}=464 k J$, Calculate enthalpy change when $2.38 g$ of carbon monoxide (CO) vapourises at its normal boiling point. Question 11. (ii) Due to settling of solid $A g C l$ from solution, entropy decreases. The total entropy is the sum of the three contribution. In what way internal energy is different from enthalpy ? The lattice enthalpy of an ionic compound is the enthalpy when one mole of an ionic compound present in its gaseous state, dissociates into its ions. You can access free study material for all three subject’s Physics, Chemistry and Mathematics. Clarify concepts to prepare for Organic Chemistry. Education Franchise × Contact Us. Calculate the work done for the expansion of gas from state (1) to state (2) at 298 K. An ideal gas is allowed to expand against a constant pressure of 2 bar from 10 L to 50 L in one step. Derive the relationship between ΔH and ΔU for an ideal gas. Download free printable worksheets Chemistry pdf of CBSE and kendriya vidyalaya Schools as per latest syllabus in pdf, CBSE Class 11 Chemistry Worksheet - Thermodynamics (1) CBSE,CCE and NCERT students can refer to the attached file. What will be the value of ΔH for the cycle as a whole? Free PDF download of Important Questions for CBSE Class 11 Chemistry Chapter 6 - Thermodynamics prepared by expert Chemistry teachers from latest edition of CBSE(NCERT) books. This question bank is designed, keeping NCERT in mind and the questions are updated with respect to upcoming Board exams. Some basic concepts of chemistry It is mainly based on three laws of thermodynamics. CBSE Class 11 - Chemistry - Thermodynamics Thermodynamics (Short Q & A) Q1: Define Thermodynamics Answer: It is a physical science that deals with quantitative relation between heat and mechanical energy. (i) Both A and R are true and R is the correct explanation of A. This is your solution of MCQ: Chapter 6 - Thermodynamics, Class 11, Chemistry JEE Notes | EduRev search giving you solved answers for the same. Chemistry. so $\mathrm{NO}(g)$ is unstable. It contains an elaborate explanation to the most commonly asked questions. (ii) The enthalpy of two moles of ZnO is more than the total enthalpy of two moles of Zn and one mole of oxygen by 693.8 kJ. How many times is molar heat capacity than specific heat capacity of water ? NCERT Books Class 11 Chemistry: The National Council of Educational Research and Training (NCERT) publishes Chemistry textbooks for Class 11. Find the solution to all questions covered in chapter 6 of NCERT class 11 Chemistry book. Practising them will clear the concepts of students and help them in understanding the different ways in which a question can be framed from this chapter. The enthalpy change $(\Delta H)$ for the reaction: $N_{2}(g)+3 H_{2}(g) \rightarrow 2 N H_{3}(g)$, $\Delta H-92.38 k J=-92380 J, R=8.314 J K^{-1} \mathrm{mol}^{-1}$, $-92380=\Delta U-2 \times 8.314 \times 298$, $\Delta U=-92380+4955=-87425 J=-87.425 k J$, For the water gas reaction $\left.\mathrm{Q}_{5} \text { ) }+\mathrm{H}_{2} \mathrm{Q}(g) \rightleftharpoons \mathrm{C} Q_{g}\right)+\mathrm{H}_{2}(\mathrm{g})$. Thermodynamics of Class 11 The branch of chemistry which deals with energy changes involved in chemical reactions is called thermochemistry. (iii) how and at what rate these energy transformations are carried out. Chemistry-XI. Red phosphorus reacts with liquid bromine as: $2 P(s)+3 B r_{2}(l) \rightarrow 2 P B r_{3}(g) \Delta_{r} H^{\circ}=-243 k J m o l^{-1}$. of water vaporised $=\frac{10}{18}=0.56$, $\therefore W=-p_{e x} \Delta V \quad\left(\Delta V=\frac{n R T}{P_{e x t}}\right)$, $=-p_{e x} \frac{n R T}{P_{e x t}}=-n R T$, $=-0.56 \times 8.314 \times 10^{-3} \times 373.15=-1.737 k J$, $\Delta U=\Delta H-P \Delta V=\Delta H-n R T$, Calculate the bond enthalpy of $H C l .$ Given that the bond enthalpies of $H_{2}$ and $C l_{2}$ are $430 \mathrm{kJ} \mathrm{mol}^{-1}$ and $242 \mathrm{kJ} \mathrm{mol}^{-1}$ respectively and $\Delta \mathrm{H}_{f}^{\circ}$ for $H C l s-95 k J m o l^{-1}$, $\Delta H_{\text {Reaction}}=\Sigma \Delta H^{\circ}$ $f$ (Products) $-\Sigma \Delta H^{\circ}$ f $(\text {Reactants})$, Calculate $\Delta S$ when 1 mole of steam at $100^{\circ} \mathrm{C}$ is converted into ice at $0^{\circ} \mathrm{C}$. Here you can get Class 11 Important Questions Chemistry based on NCERT Text book for Class XI. Calculate the value of standard Gibb’s energy change at 298 K and predict whether the reaction is spontaneous or not. Home » Class 11 » Chemistry » Thermodynamics » Enthalpy. The NCERT Chemistry Books are based on the latest exam pattern and CBSE syllabus. These important questions will play significant role in clearing concepts of Chemistry. (i) At what temperature the reaction will occur spontaneously from left to right? Class 11 Detailed Chapter Notes - Thermodynamics, Class 11, Chemistry | EduRev Notes Summary and Exercise are very important for perfect preparation. Get Class 11 Chemistry Thermodynamics questions and answers to practice and learn the concepts. If you have any query regarding NCERT Solutions for Class 11 Chemistry at Work Chapter 6 Thermodynamics, drop a … These CBSE NCERT Class 11 Chemistry MCQs have been developed by experienced teachers of StudiesToday.com for benefit of Class 11 students. (ii) $\quad \Delta S=+v e$ because aqueous solution has more disorder than solid. (iii) ΔS (system) decreases but ΔS (surroundings) increases. Write the mathematical relation which relates these three parameters. Molar mass of phosphorus $=30 \mathrm{gmol}^{-1}$, Moles of $P=\frac{10.32}{31}=0.333 \mathrm{mol}$, Enthalpy change for 2 mole of $P=-243 \mathrm{kJ}$, Enthalpy change for 0.333 mole of $P=-\frac{243}{2} \times 0.333$, Standard enthalpy of vapourisation of benzene at its boiling point is $30.8 \mathrm{kJ} \mathrm{mol}^{-1} .$ For how long would a $100 \mathrm{Welectric}$ heater have to operate in order to vapourise $100 \mathrm{g}$ of benzene at its boiling point. 18.0 g of water completely vapourises at 100°C and 1 bar pressure and the enthalpy change in the process is 40.79 kJ mol. Expansion of a gas in vacuum is called free expansion. (ii), (ii) $C_{( \text {graphite) } }+O_{2}(g) \rightarrow C O_{2}(g) ; \Delta_{r} H^{\circ}=-393 \mathrm{kJ} \mathrm{mol}^{-1}$, (iii) $\times 2: 2 H_{2}(g)+O_{2}(g) \rightarrow 2 H_{2} O(l) ; \Delta_{r} H^{o}=-572 k J m o r^{1}$, (iv) $\quad C(g)+2 H_{2}(g)+2 O_{2}(g) \longrightarrow C O_{2}(g)+2 H_{2}^{\circ} O$, $\Delta_{r} H^{\circ}=-965 \mathrm{kJmol}^{-1}$, Subtract eq. $g$ of $C O_{2}$ from carbon and dioxygen gas. Heat released in the formation of 44g of C0 2 = 393.5 kj. G=H -TS. Enter OTP. (iv) the feasibility of a chemical reaction. 01.Physical World; 02. The standard Gibbs energy of reaction (at $1000 K)$ is $-8.1$ $k J m o l^{-1} .$ Calculate its equilibrium constant. Class 9+10 – Foundation for IIT Physics; Class 9+10 – Foundation for IIT Chemistry; View All Courses; Live Tutoring; Study Material; Test Series; Watch Video Lectures; LIVE Class Login; Doubts; Contact. Home >> Questions>> Chemistry. The volume of gas is reduced to half from its original volume. The temperature of calorimeter rises from $294.05 K$ to $300.78 K .$ If the heat capacity of calorimeter is $8.93 \mathrm{kJK}^{-1}$, calculate the heat transferred to the calorimeter. A-1, Acharya Nikatan, Mayur Vihar, Phase-1, Central Market, New Delhi-110091. $\Delta_{r} G^{\circ}=-2.303 R T \log K \quad$ or $\log K=\frac{-\Delta_{r} G}{2.303 R T}$, $\Delta_{r} G^{o}=-8.1 k J m o l^{-1}, T=1000 K$, $R=8.314 \times 10^{-3} \mathrm{kJ} \mathrm{mol}^{-1} \mathrm{K}^{-1}$, $\log K=-\frac{-8.1}{2.303 \times 8.314 \times 10^{-3} \times 1000}$ or $K=2.64$. NCERT Solutions for Class 11 Chemistry: Chapter 6 (Thermodynamics) can be found on this page. 6.4. Question 1. Design in accordance with the latest CBSE syllabus as well as examination pattern, this books aid students in getting good marks in the exam. MCQ Questions for Class 11 Chemistry with Answers were prepared based on the latest exam pattern. Since Gibbs energy change is positive, therefore, at the reaction is not possible. 6.3. The processes which occur spontaneously are. $\therefore \quad \Delta S_{\text {total}}=-26.0445-5.62-5.26$, $\Rightarrow \quad-36.9245 \mathrm{cal} K^{-1} \mathrm{mol}^{-1}$, Download or view Key Concepts of Thermodynamics & Thermochemistry. We have provided Equilibrium Class 11 Chemistry MCQs Questions with Answers to help students understand the concept very well. Chapter Wise Important Questions Class 11 Chemistry. Give suitable examples. Here enthalpy of CH₄G is … The chemistry class 11 syllabus aims to give the students an overall picture of what fundamentals of higher chemistry look like. Free PDF download of Important Questions for CBSE Class 11 Chemistry Chapter 6 - Thermodynamics prepared by expert Chemistry teachers from latest edition of CBSE(NCERT) books. The enthalpy of vaporisation of liquid diethyl ether $\left[\left(C_{2} H_{5}\right)_{2} O\right]$ is $26.0 \mathrm{kJ} \mathrm{mol}^{-1}$ at its boiling point $\left(35^{\circ} \mathrm{C}\right)$. Thermodynamics Chemistry Chapter 6 • Important Terms and Definitions System: Refers to the portion of universe which is under observation. Enthalpy. In what way is it different from bond enthalpy of diatomic molecule ? You also get idea about the type of questions and method to answer in your Class 11th examination. Here we have provided NCERT Exemplar Problems Solutions along with NCERT Exemplar Problems Class 11. Multiple Choice Questions (Type-I) 1800-212-7858 / 9372462318. 11th Chemistry chapter 06 Thermodynamics have many topics. Given that ΔH = 0 for mixing of two gases. CBSE Important Questions for Class 11 Chemistry, Kerala Board Class 11th Model Question Paper, NCERT Important Questions for Class 11 Chemistry, NCERT Solutions for Class 8 Sanskrit Chapter 11 सावित्री बाई फुले, NCERT Solutions for Class 12th Macroeconomics : Chapter 6 – Open Economy Macroeconomics, Class 11 Important Questions for Chemistry - Equilibrium. (ii) gas in a container contracting into one corner. Compare it with entropy decrease when a liquid sample is converted into a solid. Which of the following statements is correct? Our social links. (i) flow of heat from colder to warmer body. Show that for an ideal gas, the molar heat capacity under constant volume conditions is equal to 3/2, At $(T+1) K,$ the kinetic energy per mole $\left(E_{k}\right)=3 / 2 R(T+1)$ Therefore, increase in the average kinetic energy of the gas for $1^{\circ} \mathrm{C}(\text { or } 1 \mathrm{K})$ rise in temperature $\Delta E_{k}=3 / 2 R(T+1)-3 / 2 R T=3 / 2 R$, When the gas is heated to raise its temperature by $1^{\circ} \mathrm{C},$ the increase in its internal energy is equal to the increase in kinetic energy, i.e., $\Delta U=\Delta E_{K}$, Now $C_{v}=\frac{\Delta U}{\Delta T}$ and $\Delta T=1^{\circ} \mathrm{C}$, Calculate the number of $k J$ necessary to raise the temperature of $60.0 \mathrm{g}$ of aluminium from $35-55^{\circ} \mathrm{C} .$ Molarheat capacity of $A l$ is $24 J m o l^{-1} K^{-1}$, Here, $C_{m}=24.0 \mathrm{J} \mathrm{mol}^{-1} \mathrm{K}^{-1} ; n=\frac{60}{27}=2.22 \mathrm{mol}$, \[ c=2.22 \mathrm{mol} \times 24.0 \mathrm{J} \mathrm{mol}^{-1} \mathrm{K}^{-1}=53.28 \mathrm{JK}^{-1} \], Now, $q=53.28 \mathrm{JK}^{-1} \times \Delta T$, $=53.28 \mathrm{JK}^{-1} \times 20 \mathrm{K}=1065.6 \mathrm{V}$ or $1.065 \mathrm{kJ}$. Last Updated on May 3, 2020 By Mrs Shilpi Nagpal 1 Comment. If not at what temperature, the reaction becomes spontaneous. Thermodynamics - Chemistry Notes, Questions and Answers, Free Study Material, Chapter wise Online Tests. Q2: Which law of thermodynamics evaluate thermodynamic parameters? Predict the sign of entropy change in the following reactions: (i) $\quad \mathrm{O}_{2}(g)+2 S O_{2}(g) \rightarrow 2 S O_{3}(g)$, (ii) $\quad \mathrm{CaC}_{2} \mathrm{O}_{4}(\mathrm{s}) \rightarrow \mathrm{CaCO}_{3}(\mathrm{s})+\mathrm{CO}(\mathrm{g})$, (iii) $2 \mathrm{H}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$, (iii) $\quad \Delta \mathrm{S}=-\mathrm{ve}$. , the system pressure at 300 K, the reaction will occur spontaneously from left to right 's! It directly by experiment = 0 for mixing of two gases will diffuse into another. Containing a few molecules NEET UG medical exams their standard states are taken as zero expanded state. 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